n(t)= c - (d - 4t)squared

(can't get a square to show up on here so when i say its squared, it is)

At time t=0 a ball was thrown upward from an initial height of 6ft. Untill the ball hit the ground, its height, in feet, after "t" seconds was given by the function "n" above, in which "c" and "d" are positive constants. If the ball reached its momentum height of 106ft at the time t=2.5 what was the height in feet of the ball at time t=1?

can you figure this out? I can't ^^