Otakuite+ | Posted 01/12/10 | Reply
very good almagest, exactly how i wanted it worked out. kudos to you XD
Otakuite | Posted 01/12/10 | Reply
x = price of toffies y = price of bonbons
2x+3y=4.5 13x+5y=10.35
By rearranging the first equation, we find that: x=(4.5-3y)/2
Plug that value in for x in the second equation: 13[(4.5-3y)/2]+5y=10.35
Solve for y and find that y is approximately 1.30
Plug the y value back into the rearranged first equation to find x: x=(4.5-3(1.30))/2
We find that x is approximately 0.30
So the cost of 38 toffies and 58 bonbons is found as follows: 38x+58y=? 38(0.30)+58(1.30)=11.4+75.4=86.8
Final answer: $86.80 (This is an approximation though because x and y were approximate values.)
I love math, what can I say? =P
MrLeitexxx
Otakuite+ | Posted 01/12/10 | Reply
very good almagest, exactly how i wanted it worked out. kudos to you XD
Almagest
Otakuite | Posted 01/12/10 | Reply
x = price of toffies
y = price of bonbons
2x+3y=4.5
13x+5y=10.35
By rearranging the first equation, we find that:
x=(4.5-3y)/2
Plug that value in for x in the second equation:
13[(4.5-3y)/2]+5y=10.35
Solve for y and find that y is approximately 1.30
Plug the y value back into the rearranged first equation to find x:
x=(4.5-3(1.30))/2
We find that x is approximately 0.30
So the cost of 38 toffies and 58 bonbons is found as follows:
38x+58y=?
38(0.30)+58(1.30)=11.4+75.4=86.8
Final answer: $86.80
(This is an approximation though because x and y were approximate values.)
I love math, what can I say? =P
Last edited by Almagest at 12:33:10 AM EST on January 12, 2010.